 | | | getSkeleton | getSkeleton 2004-04-02 - By Romano Ivanovic
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thank you people......it works great!!!
-- -- Original Message -- --
From: Bradley Gabe
To: XSI@(protected)
Sent: Friday, April 02, 2004 12:09 AM
Subject: Re: [scripting] getSkeleton
Sorry... looks as though lucas mail server has developed a stutter.
Or better yet, get yourself a pointer to the chain root. All the bones
and the effector are properties of the chain root.
var oChn = ActiveSceneRoot.FindChild("nameOfChainRoot");
var oBones = oChn.Bones;
var oEff = oChn.Effector;
LogMessage(oChn);
for(var i = 0; i<oBones.count; i++){
LogMessage(oBones(i));
}
LogMessage(oEff);
Hi, if you simply want to get all children under the chain root you could
try this:
' You have to select the chain root first for this to work
set oChainRoot = selection(0)
set oChildren = oChainRoot.findchildren
for each oChild in oChildren
logmessage oChild
next
Cheers,
F.
Romano Ivanovic wrote:
hi,
Im looking for a command that gives me names of all the bones and
children in a root!
GetSkeleton is a good command but it gives me just the root, bones and
effector.....not children!
thx
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--
Bradley R. Gabe
Industrial Light & Magic
--
Bradley R. Gabe
Industrial Light & Magic
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<DIV><FONT face=Arial size=2>thank you people......it works
great!!!</FONT></DIV>
<DIV> </DIV>
<DIV> </DIV>
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<DIV style="FONT: 10pt arial">-- -- Original Message -- -- </DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A href="mailto:bgabe@(protected)" title=bgabe@(protected)>Bradley Gabe</A> </DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A href="mailto:XSI@(protected)"
title=XSI@(protected)>XSI@(protected)</A> </DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Friday, April 02, 2004 12:09
AM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> Re: [scripting]
getSkeleton</DIV>
<DIV><BR></DIV>Sorry... looks as though lucas mail server has developed a
stutter.<BR><BR>
<BLOCKQUOTE cite="mid406C7737.7040709@(protected)" type="cite"> Or better
yet, get yourself a pointer to the chain root. All the bones and the
effector are properties of the chain root.<BR><BR><TT>var oChn =
ActiveSceneRoot.FindChild("nameOfChainRoot");<BR>var oBones =
oChn.Bones;<BR>var oEff =
oChn.Effector;<BR><BR>LogMessage(oChn);<BR></TT><TT>for(var i = 0;
i<oBones.count; i++){<BR>
LogMessage(oBones(i));<BR>}<BR>LogMessage(oEff);<BR><BR><BR></TT>
<BLOCKQUOTE cite="mid001901c41802$46df3150$8202a8c0@(protected)" type="cite"><PRE
wrap="">Hi, if you simply want to get all children under the chain root you
could
try this:
' You have to select the chain root first for this to work
set oChainRoot = selection(0)
set oChildren = oChainRoot.findchildren
for each oChild in oChildren
logmessage oChild
next
Cheers,
F.
Romano Ivanovic wrote:
</PRE>
<BLOCKQUOTE type="cite"><PRE wrap="">hi,
Im looking for a command that gives me names of all the bones and
children in a root!
GetSkeleton is a good command but it gives me just the root, bones and
effector.....not children!
thx
</PRE></BLOCKQUOTE><PRE wrap=""><!---->
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</PRE></BLOCKQUOTE><BR><PRE class=moz-signature cols="72">--
Bradley R. Gabe
Industrial Light & Magic
</PRE></BLOCKQUOTE><BR><PRE class=moz-signature cols="72">--
Bradley R. Gabe
Industrial Light & Magic
</PRE></BLOCKQUOTE></BODY></HTML>
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