 | | | getSkeleton | getSkeleton 2004-04-01 - By Bradley Gabe
Back
Sorry... looks as though lucas mail server has developed a stutter.
> Or better yet, get yourself a pointer to the chain root. All the
> bones and the effector are properties of the chain root.
>
> var oChn = ActiveSceneRoot.FindChild("nameOfChainRoot");
> var oBones = oChn.Bones;
> var oEff = oChn.Effector;
>
> LogMessage(oChn);
> for(var i = 0; i<oBones.count; i++){
> LogMessage(oBones(i));
> }
> LogMessage(oEff);
>
>
>>Hi, if you simply want to get all children under the chain root you could
>>try this:
>>
>>' You have to select the chain root first for this to work
>>set oChainRoot = selection(0)
>>
>>set oChildren = oChainRoot.findchildren
>>for each oChild in oChildren
>> logmessage oChild
>>next
>>
>>Cheers,
>>F.
>>
>>
>>Romano Ivanovic wrote:
>>
>>
>>>hi,
>>>Im looking for a command that gives me names of all the bones and
>>>children in a root!
>>>GetSkeleton is a good command but it gives me just the root, bones and
>>>effector.....not children!
>>>
>>>thx
>>>
>>>
>>
>>---
>>Unsubscribe? Mail Majordomo@(protected) with the following text in body:
>>unsubscribe xsi
>>
>>
>>
>
>--
>Bradley R. Gabe
>Industrial Light & Magic
>
>
--
Bradley R. Gabe
Industrial Light & Magic
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;charset=ISO-8859 (See http://ISO-8859.ora-code.com)-1">
<title></title>
</head>
<body>
Sorry... looks as though lucas mail server has developed a stutter.<br>
<br>
<blockquote type="cite" cite="mid406C7737.7040709@(protected)"> Or
better yet, get yourself a pointer to the chain root. All the bones and
the effector are properties of the chain root.<br>
<br>
<tt>var oChn = ActiveSceneRoot.FindChild("nameOfChainRoot");<br>
var oBones = oChn.Bones;<br>
var oEff = oChn.Effector;<br>
<br>
LogMessage(oChn);<br>
</tt><tt>for(var i = 0; i<oBones.count; i++){<br>
LogMessage(oBones(i));<br>
}<br>
LogMessage(oEff);<br>
<br>
<br>
</tt>
<blockquote type="cite" cite="mid001901c41802$46df3150$8202a8c0@(protected)">
<pre wrap="">Hi, if you simply want to get all children under the chain
root you could
try this:
' You have to select the chain root first for this to work
set oChainRoot = selection(0)
set oChildren = oChainRoot.findchildren
for each oChild in oChildren
logmessage oChild
next
Cheers,
F.
Romano Ivanovic wrote:
</pre>
<blockquote type="cite">
<pre wrap="">hi,
Im looking for a command that gives me names of all the bones and
children in a root!
GetSkeleton is a good command but it gives me just the root, bones and
effector.....not children!
thx
</pre>
</blockquote>
<pre wrap=""><!---->
---
Unsubscribe? Mail <a class="moz-txt-link-abbreviated"
href="mailto:Majordomo@(protected)">Majordomo@(protected)</a> with the
following text in body:
unsubscribe xsi
</pre>
</blockquote>
<br>
<pre class="moz-signature" cols="72">--
Bradley R. Gabe
Industrial Light & Magic
</pre>
</blockquote>
<br>
<pre class="moz-signature" cols="72">--
Bradley R. Gabe
Industrial Light & Magic
</pre>
</body>
</html>
|
|
|