 | | | How can I get the global position of a single point of curve, which is branch de | How can I get the global position of a single point of curve, which is branch de 2004-02-21 - By Sebastian Faber
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I have a curve deformed on another curve via branch deformation. How can I
get the GLOBAL position of a single Point of this deformed curve?
Any hints are welcome
Sebastian
to get the global position of a point of a undeformed geometry would be like
this:
set oTrans = oCube.Kinematics.Local.Transform
set oPoint = oCube.ActivePrimitive.Geometry.Points(0)
set oPos = oPoint.Position
logmessage "The local position is: X "& oPos.X & " Y " & oPos.Y & " Z " &
oPos.Z
set oGlobalPos = XSIMath.MapObjectPositionToWorldSpace( oTrans, oPos)
logmessage "The world position is: X "& oGlobalPos.X & " Y " &
oGlobalPos.Y & " Z " & oGlobalPos.Z
LIGA_01 COMPUTERFILM GmbH
Sebastian Faber
Landwehrstrasse 60
D - 80336 Munich - Germany
sebastian.faber@(protected)
www.liga01.com
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