 | | | Positioning of two object faces each with different rotation values to th | Positioning of two object faces each with different rotation values to th 2005-06-15 - By DAVID STUBBS
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Hello
I would like to position faces of 2 objects together. The face dimensions may
or may not be the same. Purpose: To get exact positioning
1st cube:
I have a cube with dimensions 1 * 1 with a z rotation of 22.5
all other rotations are 0.00
2nd cube:
I have a cube with dimensions 1 * 1 with a z rotation of 0.00
all other rotations are 0.00
I would like change the (face only) of the 2nd cube so that
it has the same angle of 22.5 the first cube but not the location.
later I will postion at the same location
without changing the x and y coords
without distorting the cubes form
What I have tried:
This works:
rotation 22.5 of 1st cube - positon overlap 1st cube with 2nd and use object
subtract
to cut the angle of the second cube so that faces are the same
Are there other ways as well?
Thanks
David
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<DIV>Hello </DIV>
<DIV> </DIV>
<DIV>I would like to position faces of 2 objects together. The face dimensions
may or may not be the same. Purpose: To get exact positioning
</DIV>
<DIV><BR>1st cube:<BR>I have a cube with dimensions 1 * 1 with a z rotation of
22.5<BR>all other rotations are 0.00</DIV>
<DIV><BR>2nd cube:<BR>I have a cube with dimensions 1 * 1 with a z rotation of
0.00<BR>all other rotations are 0.00</DIV>
<DIV><BR>I would like change the (face only) of the 2nd cube so that<BR>it has
the same angle of 22.5 the first cube but not the location.</DIV>
<DIV>later I will postion at the same location</DIV>
<DIV> </DIV>
<DIV>without changing the x and y coords <BR>without distorting the cubes form
</DIV>
<DIV><BR>What I have tried: </DIV>
<DIV>This works:<BR>rotation 22.5 of 1st cube - positon overlap 1st cube with
2nd and use object subtract<BR>to cut the angle of the second cube so that
faces are the same <BR></DIV>
<DIV> </DIV>
<DIV>Are there other ways as well?</DIV>
<DIV> </DIV>
<DIV>Thanks</DIV>
<DIV> </DIV>
<DIV>David</DIV>
<DIV><BR> </DIV>
<BR>
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<BR>
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