Meshes Q.s: Unfolding; Turn curved mesh into squared? 2004-08-16 - By Anthony Ware
Back Kris,
This is really quite trivial to do, but requires some tedious work on your part which you will no doubt baulk against.
Choose a face of the object on the required latitude or longitude, enter point edit mode and repeatedly do a "slice object by selected line/plane" along the chosen face. You can then further point edit the result, removing all none longitudinal or latitudinal lines and faces, resulting in a mesh with all 'lines' along the required latitude/longitude.
Anthony
> -- --Original Message-- -- > From: TSML [mailto:truespace@(protected)] On Behalf Of K M Krieger > Sent: 16 August 2004 22:16 > To: truespace@(protected) > Subject: Re: [TSML] Meshes Q.s: Unfolding; Turn curved mesh > into squared? > > At 04:08 PM 16-08-04, hans_k wrote: > >K M Krieger <pterochromics@(protected)> wrote: > > > >>I tired Pepakura > > > >Was that a freudian misspelling? ;-) > > Nah, I don't hae my glasses on and I can't type worth beans... > > > >>Pekajura does not deal well at all with "curved meshes". > > > >Of course not. When you make a model out of cardboard/paper, > the edges > >are always folded to fit to adjoining surfaces. If you take > a piece of > >paper and fold the edges, it will be flat and with stright edges. > >Pepakura has to stick to that, otherwise it would not create a valid > >model, that can actually be constructed with paper/cardboard. > >For paper models, your object have to have very few polygons. > > The edges are "flat" (i.e. where they'd be folded); that's > true by definition, since it's a mesh, but the problem is > that the program tends to disassemble little parts out from it. > > More specifically, rather thanunwrapping the curved mesh, I'm > interested in whether there is a way to convert it so that > the mesh is "striaght (meaning, all the mesh lines are > straight latitude and longitude type lines. IOW as tho' the > mesh was made from 1/4 inch wire cloth, as opposed to a bunch > of trapezoids and skewed paralleograms. > > TIA, > > - Kris K.
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