checking that an object exists 2005-04-07 - By Bernard Lebel
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On top of my head, since you got the object's fullname, I'd use the
model name as the source of a findchild() or findchildren() call. If
there is no model name in the full name then use the active scene
root.
Perhaps also a direct look up in the .children() property of objects
could work, but then you have to find out with object to look up.
In the case of objects outside the scene root scope, like partitions,
passes, layers and such (that you don't normally get via a findchild()
or findchildren() call, you may try enumelements() on the application
object (although I have not tested that suggestion).
Btw, besides the Linux limitation with the try/catch statement in
JScript, what's so wrong with exception catching? You are testing the
existence of an object, not running commands or calling methods.
PS: if by "object" you mean programming object and not just scene
object (ie parameters and properties), you can test that easily:
if( !oObject.properties( "aproperty" ) ) {
logmessage( "no" );
}
or the more elegant Pythonic way:
if not oObject.properties( 'aproperty' ): print 'no'
Cheers
Bernard
On Apr 7, 2005 2:32 PM, Brad Friedman <xsibrad@(protected)> wrote:
> Hi,
>
> I got an interesting question from someone, that I wanted to check out
> with you all.
>
> Given an object's full name, he wants to check if it exists.
>
> So there are two ways to do it.
>
> Via command: GetValue()
>
> Via object model: Dictionary.GetObject()
>
> now here's the question:
>
> Both of these solutions throw an exception if the given object does not
> exist. While you can catch the exception, I'd think this is a poor way
> to go about solving the problem. Exceptions should not be used for flow
> control. They're inherently slow (or so I've been taught time and time
> again). Is there a better fast way to check if an object exists from
> its full name that doesn't involve depending on exceptions? I can come
> up with some ways of doing it that will be inherently slow... but none
> that are fast.
>
> -brad
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